# Line slope calculator 5x+4y=40

**Straight line given by points A[0; 10] and B[4; 5]**

## Calculation:

**Slope-intercept form of line:**y = -1.25x+10

**Canonical form of the line equation:**5x+4y-40 = 0

**Parametric form of the line equation:**

x = 4t

y = -5t+10 ; t ∈ R

**Slope:**m = -1.25

**Slope angle of line: φ =**-51°20'25″ = -0.8961 rad

**X intercept:**x

_{0}= 8

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 6.247

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(4; -5)

**Normal vector: n =**(5; 4)

**Midpoint of the segment AB: M =**[2; 7.5]

**Perpendicular Bisector equation:**4x-5y+29.5 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (4; 5) ; |OB| = 6.4031**

**Scalar product OA .OB = 50**

**Angle ∠ AOB = 38°39'35″ = 0.6747 rad**